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Pupil
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posted by  bjjad on 8/23/2009 11:16:53 AM  |  status: Closed  |  Earned Karma: 50

Linear Transformations

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Linear Algebra Linear Algebra by J.B. Fraleigh and R.A. Beauregard (any edition), Addison Wesley; N/A N/A N/A
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Oracle
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(andhra university college of engg.)
posted by VENUGOPAL on 8/23/2009 12:00:57 PM  |  status: Live
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T IS FROM P3 TO R2....
P3 HAS 4 FREE VARIABLES.ITS DIMENSION IS 4 . SO IF THE TRANSFORMATION MATRIX IS A THEN
T[P3]=A*P3=R2..MEANS
A[2,4]*P3[4,1]=R2[2,1]
HENCE THE TRANSFORM MATRIX IS OF ORDER [2,4]
SO ITS MAXIMUM RANK CAN BE 2, SINCE 2 IS THE MAXIMUM ORDER OF THE SQUARE DETERMINANT WE CAN HAVE FROM  A.
SINCE NUMBER OF COLUMNS IS  4 IN  A, FROM RANK -NULLITY THEOREM WE GET
2+NULLITY = 4
THAT IS NULLITY CAN BE MINIMUM 2 .
SO NULLITY OF A THE TRANSFORM MATRIX CAN NEVER BE ZERO


venugopal.a.
Oracle
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posted by RedSox123 on 8/23/2009 11:12:46 PM  |  status: Live
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If y is an element of P3, then y is of the form:
ax^3 + bx^2 + cx + d

Notice there are four unknowns (a, b, c, d).  This is the dimension of P3 (note: p3 is isomorphic to R4).  The dimension of R2 is clearly 2.  Since we are mapping a 4 dimensional space to a 2 dimensional space, the transform matrix is of dimension 2x4.

We know rank + nullity = # of columns.

The rank can be at most 2 here since there are only 2 rows (it can be 0, 1, 2 depending on tha matrix).  Further, the matrix has 4 columns.  Therefore, the nullity is at least 2 (2, 3, 4).  

As a result, the nullity cannot be 0.

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