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posted by  Dima09XX on 7/29/2009 4:36:05 PM  |  status: Closed  |  Earned Karma: 28

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Question Details:
Prove identity is true: sin6t=3sin2t-4sin32t
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Oracle
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posted by wchau on 7/29/2009 4:45:30 PM  |  status: Live
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Response Details:
We have






.
Thus .
Using the last proven identity with , we have .



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Apprentice
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posted by mukulg on 7/29/2009 4:49:20 PM  |  status: Live
Asker's Rating: Helpful   
Response Details:
LHS
=sin6t
 = sin3(2t)
 = sin (2(2t)+2t)
= sin(2(2t)cos2t)+cos(2(2t))sin(2t)
= sin2t*(2cos22t)+sin2t*(1-2sin22t)
=sin2t[2(1-sin22t)+(1-2sin22t)]
=sin2t[3-4sin22t]
=3sin2t-4sin32t
=RHS

proved...
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