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posted by  aznrunsalot on 11/3/2009 1:34:55 PM  |  status: Live  |  Earned Karma: 0

Angular Speed

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Trigonometry N/A N/A N/A 11/6/2009 at 1:34:00 PM
Question Details:
My current electric bicycle uses a friction drive system. The drive wheel has a diameter of 2.125 in and makes contact with the back tire which has a diameter of 20 in. Just like with a pulley, the linear speeds of both wheels are the same. At 17.38 mph the bicycle wheel is rotating at 292.1875 rpm. Determine the rpm of the drive wheel.

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posted by JeromeD on 11/5/2009 7:50:18 PM  |  status: Live
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velocity = rw, where w is rotation(in radians) per time θ/t

So we have:

17.38 mph = 1.0625 in * X radians/minute

convert 17.38 mph to in/min

(17.38 miles / hour) * (1 hour / 60 min) * (63360 in / mile) = (17.38/60)*63360 this is NEWv

Using that answer for NEWv

we have :

NEWv = 1.0625 * (Xradpm)

Solve for Xradpm

Xrpm = NEWv/1.0625 = Xradpm( in radians)

Now convert Xradpm from radians/min to rotations/min

Xrpm(rotations/min) = Xradpm / (2*pi)

This answer is the rotational speed of the drive wheel.
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