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posted by  watts on 11/21/2009 3:05:56 PM  |  status: Closed  |  Earned Karma: 266

series-parallel combinations12

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N/A N/A N/A N/A 11/30/2009 at 6:00:00 PM
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posted by tc7033 on 11/21/2009 4:50:33 PM  |  status: Live
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Response Details:
First, the 8 ohm and 4 ohm are in series.  Combine them to become 12 ohm
To find i, we will use current division.
i = (12/(12+6)) x 9 = 6 A

To find v, we need to find i2.

given: i1 = 9A
   i = i1 - i2
  6 = 9 - i2
3A = i2

V = 4i2
    = 12V


To find p, we must find the v for the 6 ohm.  We can use voltage division.
V for 6 ohm = (6/(6+8)) x (V for the 4 ohm resistor, which we found was 12 V)
V for 6 ohm = (36/7) V

p = vi
   = (36/7)(6)
   = (216/7) W or 30.857 W
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