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posted by  ashortfuse13 on 11/4/2007 4:27:02 PM  |  status: Closed  |  Earned Karma: 766

Polar Coordinates

Course Textbook Chapter Problem Needs by
Calculus Calculus: Concepts and Contexts (3rd) by Stewart 12.4 27E N/A
Question Details:


Convert and evaluate the given iterated integral by converting to polar coordinates.

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posted by Anonymous on 11/3/2009 4:06:06 PM  |  status: Live
Clarification Details:
isn't that drawing incorrect?  There is no y=1 bound and the area shaded should be below the y=x line to the curve sqrt(2)

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Sage
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(Aligarh Muslim University, Indian institute of Technology,Roorkee)
posted by Saiful Rahman on 11/5/2007 8:28:39 AM  |  status: Live
Asker's Rating: Helpful   
Response Details:

Since by the given limit we have

the regin of  is between the line x=y and x = √2-yi.e x2 + y2 = 2. a circle , in the first co-ordinate.
 
So in polar form we have θ=π/4 to θ=π/2.
and  r = 0 to √2
 
 =
 
=
 
 
 

 

Tags: Math, Calculus
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