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posted by  rom83 on 5/6/2009 4:28:28 AM  |  status: Live  |  Earned Karma: 2

maths.....................

Course Textbook Chapter Problem Needs by
Differential Equations N/A N/A N/A N/A
Question Details:
Q.1 

Find the intervals where the function  is increasing
and where it is decreasing.


Note: - please reply step by step.

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Oracle
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(Universidad Autónoma de Nuevo León)
posted by Dr. House on 5/6/2009 6:38:47 AM  |  status: Live
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Response Details:
Given
We find the critical number where  f '(x)=0
12x=0 
x-2=0
x+1=0
Solving for x we conclude that the critical numbers are x=0,x=2 and x=-1
f '(x) > 0 implies that f(x) is increasing  => (-1,0) U (2,∞)
f '(x) <0 implies that f(x) is decreasing => (-∞,-1) U (0,2)
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posted by Leoismyname on 5/6/2009 12:48:05 PM  |  status: Live
Asker's Rating: Helpful   
Response Details:
You need to find the first derivative:
f '(x) = 12x3 -12x2 -24x
f '(x) = 12x (x2 - x - 2)
f '(x) = 12x (x + 1) (x - 2)
Let f '(x) = 0
We have x = 0, x = -1 or x = 2
Follow this chart

There is a method to make this chart really fast but it is quite long to explain. So the most practical way is to plug in the points between roots to see if it is positive or negative (this only use for polynomial function, it is different for rational function)
As you know, when f '(x) > 0, it means the slope greater than 0, so f (x) is increasing. The same when f '(x) < 0, f (x) is decreasing
So the answer is
Decreasing: (-∞, -1) U (0, 2)
Increasing: (-1, 0) U (2, +∞)

Hope this helps and please rate me as I took time to solve it, thank you

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