Using polar coordinates, evaluate the integral which gives the area which lies in the first quadrant between the circles x2+y2=142 and x2−14x+y2=0.
x2−14x+y2=0. ==>
x2+y2=14x r
2=142 r cos θ ==> r= 14 cosθ
r=r
14 = 14 cosθ
cosθ= 1
θ= 0 and θ=2π
A= Integrate[Integrate[r,{r,14Cos[t],14}],{t,0,2*Pi}] = 98π
A/4= 98π /4= 49π / 2