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posted by  Bigjd on 11/1/2009 3:10:57 PM  |  status: Closed  |  Earned Karma: 50

Evaluate the Integral (show work)

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Calculus N/A N/A N/A 11/1/2009 at 11:00:00 AM
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The BIG JD
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posted by velixy on 11/1/2009 3:41:54 PM  |  status: Live
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   =   =
x= √5     tan t  => t= arctan(√5  /  x)
dx =  √5  (   tan2 t  +1) dt  = √5  (   sec2 t ) dt 
=   =   = 5 tant -5 t  +C
= 5 x / √5     -  5  arctan(√5  /  x)  + C  ANSWER 
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