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posted by  Novaworks on 11/3/2009 3:09:36 PM  |  status: Closed  |  Earned Karma: 1145

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Course Textbook Chapter Problem Needs by
Calculus N/A N/A N/A 11/4/2009 at 10:00:00 PM
Question Details:
Find f.
f ''(x) = 20x3 + 12x2 + 6
f(0) = 9
f(1) = 7
f(x) =
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A particle is moving with the given data. Find the position of the particle.
a(t) = cos(t) + sin(t)
s(0) = 2
v(0) = 3
s(t) =
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posted by MathWiz1994 on 11/3/2009 4:04:01 PM  |  status: Live
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Response Details:
Solve these by integrating, remembering to include the constants of integration, and plugging in the given values to solve for the constants of integration.
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For the first problem:
f''(x)=20x3+12x2+6
f'(x)=5x4+4x3+6x+C1
f(x)=x5+x4+3x2+C1x+C2
f(0)=(0)5+(0)4+3(0)2+C1(0)+C2
C2=9
f(x)=x5+x4+3x2+C1x+9
f(1)=(1)5+(1)4+3(1)2+C1(1)+9
7=14+C1
C1=-7
f(x)=x5+x4+3x2-7x+9
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For the second problem:
a(t)=cos(t)+sin(t)
v(t)=sin(t)-cos(t)+C1
v(0)=sin(0)-cos(0)+C1
3=0-(1)+C1
C1=4
v(t)=sin(t)-cos(t)+4
s(t)=-cos(t)-sin(t)+4t+C2
s(0)=-cos(0)-sin(0)+4(0)+C2
2=-(1)-0+0+C2
C2=3
s(t)=-cos(t)-sin(t)+4t+3
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