This is an ideal gas law problem: PV=nRT
Solving for V:
V=nRT/P
where
V=volume in L
n=amount of substance in mols
R=gas constant
T=temperature in °K
P=pressure in torr
Since you gave the amount of CO2 in grams we convert that to mols by dividing by the molar mass of CO2 (44.01g)
n=0.327/44.01=0.0074 mol
Plug in your values and you get:
V=(0.0074 mol)(62.363 L torr/°K mol)(273+22.5°K) / 755 torr
V=0.1814 L = 181.4 mL