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posted by  sommosam on 7/3/2009 4:06:07 PM  |  status: Live  |  Earned Karma: 50

Nodle & Mesh Analysis

Course Textbook Chapter Problem Needs by
N/A Foundations of electronics Circuit and DEVICES N/A N/A N/A
Question Details:
Determine V4 ?



Resistors are,  6Ω,  4Ω,  8Ω
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posted by sommosam on 7/3/2009 10:35:28 PM  |  status: Live
Clarification Details:
is this by Nodle  and Mesh analysis?

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posted by Shree_vani(MNK) on 7/3/2009 5:29:07 PM  |  status: Live
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Response Details:
Converting the current sources into voltage sources, the circiur will be as shown below
The 5A current source in parallel with 6Ω resistor is replaced by a voltage source = (5)(6) = 30V in series with 6Ω
The 4A current source in parallel with 8Ω resistor is replaced by a voltage source = (4)(8) = 32V in series with 8Ω
The current I in the circuit will be
The voltage across the 4Ω resistor will be
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posted by Shree_vani(MNK) on 7/4/2009 12:00:07 AM  |  status: Live
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Response Details:
Using Mesh analysis
Current through 6Ω is I + 5A
Current through 8Ω is I - 4A
Applying KVL to the loop
12 = 8 ( I - 4) + 6 ( I +5) + 4I
12 = 8I - 32 + 6I +30 +4I
18I = 14
I = 0.78 A
Voltage across 4Ω will be
V4Ω = 4I
V4Ω = 4(0.78) = 3.12V
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