Data Given
Vin(rms) = 10V
Diode is ideal
To find
Average dc output voltage
Sketch the wave forms
Solution
The peak input voltage is given by
VP = √2Vinrms
Vp = (1.414)(10) = 14.14V
During the negative half cycle, the diode is forward biased and act as a short circuit. The current flows through the capacitor and the capacitor charges to the peak input voltage Vp . The output voltage will be Vout = 0V.
During the positive half cucle, the diode is reversed biased and act as a open circuit. Now the output voltage will be, the voltage across the capacitor which is Vp (being charged during negative half cycle) plus the peak input voltage Vp , thats is Vout = 2Vp
Waveforms
The average dc output voltage is Vdc = 14.14V