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posted by  511 on 11/6/2009 1:07:25 PM  |  status: Closed  |  Earned Karma: 60

Electronics Fundamentals Q1

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N/A N/A N/A N/A 11/7/2009 at 11:00:00 PM
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Sage
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posted by Chelsea_fan(MNK) on 11/6/2009 2:04:42 PM  |  status: Live
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b)the average DC voltage across RL=14V
diode has a voltage drop of .7 V
so voltage before rectification=14.7 V
so voltage on secondary terminal of centre tapped transformer=14.7*2=29.4 V

c)now, C=Idc/2fΔV
here f=60
Idc=VRL/RL=14/120=.117 A
ΔV=.5-(-.5)=1V

so C=.99 mF

d)max voltage across diodes=14-(-14.7)=28.7
for a 50% safety margin a diode with PIV rating of 60V
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