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Pupil
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posted by  511 on 11/6/2009 1:10:07 PM  |  status: Closed  |  Earned Karma: 60

Electronics Fundamentals Q4

Course Textbook Chapter Problem Needs by
N/A N/A N/A N/A 11/7/2009 at 7:00:00 PM
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Sage
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(IIT Kharagpur)
posted by Chelsea_fan(MNK) on 11/6/2009 2:23:38 PM  |  status: Live
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Response Details:
we know,

current thru a diode is given by..,
I=IS(eVd/nVt-1)
here Is=reverse saturation current
given,
Vt=25mV
n=1
Is=1.5*10-14

Vd=2/3 V

so putting all values,
I=5.72 mA



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