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posted by  hooky on 11/6/2009 6:44:52 PM  |  status: Closed  |  Earned Karma: 25

Clamped Capacitor / average dc value

Course Textbook Chapter Problem Needs by
Electrical Engineering Microelectronic Circuits (5th) by Sedra, Smith Diodes N/A 11/1/2009 at 3:00:00 PM
Question Details:


A clamped capacitor  which uses an ideal diode is supplied with a

    sine wave of 10V rms. What is the average dc value of the resulting

    output? Sketch & explain output waveform.          


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Sage
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posted by Chelsea_fan(MNK) on 11/7/2009 1:50:05 AM  |  status: Live
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Response Details:

Vin(rms) = 10V

Diode is ideal

The peak input voltage is given by

VP = √2Vinrms

Vp = (1.414)(10) = 14.14V

During the negative half cycle, the diode is forward biased and act as a short circuit. The current flows through the capacitor and the capacitor charges to the peak input voltage Vp . The output voltage will be Vout =  0V.

During the positive half cucle, the diode is reversed biased and act as a open circuit. Now the output voltage will be, the voltage across the capacitor which is Vp (being charged during negative half cycle) plus the peak input voltage Vp , thats is Vout = 2Vp


Waveforms
The average dc output voltage is Vdc = 14.14V
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