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posted by  SUJagkrista on 10/7/2009 1:25:14 PM  |  status: Closed  |  Earned Karma: 50

Dynamics : Kinematics of particles

Course Textbook Chapter Problem Needs by
N/A N/A N/A N/A 10/8/2009 at 12:00:00 PM
Question Details:

A projectile is fired with an initial velocity of 800 ft/sec at

a target B located 2,000 ft above the gun A and at a

horizontal distance of 12,000 ft.

Find:

a) The value of the firing angle α

b) The time of flight (tAB) from A to B.
Im having trouble finding out  Alpha .. Please help me if you can ! Show all your work please !
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AAnswers:

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Oracle
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posted by PhysicsPhanatic on 10/7/2009 2:29:52 PM  |  status: Live
Asker's Rating: Helpful   
Response Details:
Since you are having trouble with part (a) I will help you with that part, but you should be able to do part (b) by simple substitution after part (a) is complete.
So first, break the problem into horizontal and vertical components. The horizontal velocity is
The distance traveled will be 12,000 ft, so the time can be found by
Solve for t:
Now the vertical components of the equation are
Substitute for the time and the location of 2000 ft:
Use the substitution that .
Rearrange the equation:
Solve the quadratic equation above to get:
Solve for α:
Either angle will reach the target.
swb07c
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