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posted by  Anonymous on 11/1/2009 1:58:00 AM  |  status: Closed  |  Earned Karma: 25

moment of inertia about the neutral axis

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Mechanics of Materials Mechanics of Materials (4th) by Beer, Johnston, DeWolf 4 2P 11/1/2009 at 8:00:00 PM
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For chapter 4 problem 2 a couple force M=5kip-in is acting upwards in a vertical plane on the end of a pipe. I am required to find the σ at points a and b. These points are located at the apex of both the outer and inner diameters respectively.The extended pipe has an inner diameter of 1.2in and and outer diameter of 1.6in. Please explain how the moment of inertia = π/64(D^4-d^4). I thought the equation should be .25π*r^4. Where does the # 64 come from why is the whole diameter used instead of the radius?
Please help at your earliest opportunity. Thanks
C
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posted by Jemmi on 11/1/2009 8:23:48 PM  |  status: Live
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