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posted by  hello99 on 11/3/2009 3:52:49 AM  |  status: Closed  |  Earned Karma: 25

Soltuion for this problem using a different diagram?

Course Textbook Chapter Problem Needs by
Classical Mechanics Vector Mechanics for Engineers: Statics and Dynamics (7th) by Beer, Johnston 4 81P 11/4/2009 at 7:00:00 PM
Question Details:
Hi

Could anyone solve this same problem but with the different measurements and values as shown in the following figure:
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posted by lorven on 11/3/2009 8:35:54 PM  |  status: Live
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posted by hello99 on 11/3/2009 8:46:07 PM  |  status: Live
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Hi,

I got B = 375N @ 36.87 degrees

and T = 300N

because

ΣFx=0
=> Bcosθ - T = 0
=> T=Bcos(36.87) = 0.8B

ΣFy=0
=> T - 75N - Bsin(36.87) = 0
=>(0.8B)-75N-(0.6B)=0
=>B=375N @ 36.87 degrees

Thus

T=0.8B = 0.8(375N) = 300N
=>T=300N



Where did I go wrong?
(SME)
posted by lorven on 11/4/2009 4:21:26 AM  |  status: Live
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