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posted by  Bohar on 11/5/2009 3:07:51 AM  |  status: Closed  |  Earned Karma: 55

mole fraction

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Thermodynamics N/A N/A N/A 11/6/2009 at 12:00:00 PM
Question Details:
calculate the mole fraction of the components in a two component mixture for which the entropy of mixing is a maximum.
Abdul
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Oracle
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posted by kwyjibo on 11/5/2009 5:52:40 PM  |  status: Live
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Response Details:
ΔS = -N*R*[x*lnx + (1-x)*ln(1-x)]

dΔS/dx = -N*R*[ lnx + 1 - (1-x)/(1-x) - ln(1-x)] = 0

-N*R*[lnx - ln(1-x)] = 0

ln x = ln(1-x)

x = 1-x

x = 0.5
the mol fraction of the other component is also 0.5 (= 1 - 0.5 )
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