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posted by  Bdart711 on 9/17/2007 12:53:41 AM  |  status: Live  |  Earned Karma: 208

Friction and tension on an inclined plane

Course Textbook Chapter Problem Needs by
Calculus Based Physics Physics (7th) by Cutnell, Johnson 4 76P N/A
Question Details:
A 194-kg log is pulled up a ramp by means of a rope that is parallel to the surface of the ramp. The ramp is inclined at 30.8 ° with respect to the horizontal. The coefficient of kinetic friction between the log and the ramp is 0.796, and the log has an acceleration of 0.813 m/s2. Find the tension in the rope.
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posted by Anonymous on 10/1/2009 9:50:33 PM  |  status: Live
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can you please put the actual numbers in the equation instead of just the symbols?
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posted by 3n2entertainer on 11/7/2009 9:52:33 AM  |  status: Live
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what is  μg?

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posted by Franklyn on 9/17/2007 3:31:20 AM  |  status: Live
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Response Details:
mass m = 194 kg
angle of inclination θ = 30.8 o
co. eff of kinetic friction μ = 0.796
acceleration of the log  a= 0.813 m /  s 2
 
from fig  T  sin ( 30.8 ) = mg
from this we calculate tension in the rope ( T )
 
 
 
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posted by Anonymous on 2/10/2009 10:24:23 PM  |  status: Live
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520.676
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posted by zsm28 on 2/20/2009 5:18:30 PM  |  status: Live
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Response Details:
m = 194-kg, θ = 30.8o, μ = 0.796, a = 0.813 m/s2.
Tcosθ - μN = ma
N + Tsinθ - mg = 0, so N = mg - Tsinθ
Tcosθ - μ(mg - Tsinθ) = ma
∴T = m(a + μg)/(cosθ + μsinθ) = 1.32*103 N
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