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posted by  Outlaw on 7/31/2008 6:34:38 AM  |  status: Live  |  Earned Karma: 25

reply ASAP

Course Textbook Chapter Problem Needs by
Calculus Based Physics University Physics with Modern Physics (12th) by Young, Freedman 28 9E N/A
Question Details:
A straight wire carries a 10A current. ABCD is a rectangle with point D in the middle of a 1.10mm segment of the wire and point C in the wire. Find the magnitude and the direction of the magnetic field due to this segment at (a) point A; (b) point B; (c) point C.

I really need help, my homework is due tomorrow morning.
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cRequests for Clarification:

Novice
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posted by Anonymous on 10/21/2009 2:49:54 PM  |  status: Live
Clarification Details:
That is wrong, I got close to the answer but not quite, does anyone else know what it is? Due tommorow

AAnswers:

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posted by Ims on 8/1/2008 1:58:47 AM  |  status: Live
Asker's Rating: Lifesaver   
Response Details:
as magnetic field in a straight wire is  B = µoi/2πr
 
you need 'r' at different places(Like A, B, C, D)
 
at C (distance from the centre is 0 as the point is on the wire):
 
  Mag Field B = µo*10/(2π*0) = infinite
At D and B, distance from centre of wire = 1.1mm=1.1*10-3m
 
Hence B = µo*10/(2π*1.1*10-3)
 
At A: distance from centre is √(1.1mm)2*(1.1mm)2 ˜ 1.55mm =1.55*10-3m
 
Mag field at A = µo*10/(2π*1.55*10-3)
 
Hope this helps you!
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posted by Anonymous on 12/16/2008 6:15:34 PM  |  status: Live
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Response Details:
i believe you would use (μ_0/4pi)(I*dL*sin(theta))/r^2

dL is the 1.10mm segment
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posted by Anonymous on 11/6/2009 11:41:01 PM  |  status: Live
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Response Details:
I = 10 A
dl = 1.10 mm = .0011m
distance between A and B = 14cm = .14m
distance between B and C = 5cm = .05m
a) point A
Use Eq. (28.5)
B = 
   = 4.00 x 10-7 T
 
b) point B
Use Eq. (28.5)
B =
   = 1.52 x 10-8 T
 
c) point C
Use Eq. (28.5)
B =
   = 0
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