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posted by  Devil HSN on 2/17/2009 11:39:48 PM  |  status: Live  |  Earned Karma: 97

Q#1 : total work - :-(( !! life-saver !! )):-

Course Textbook Chapter Problem Needs by
Calculus Based Physics N/A N/A N/A N/A
Question Details:
Find the total work done by the force shown in the figure below as the object on which it acts moves.




Part A:
from x = 0 to x = 3 km and
W = ................ kJ

Part B:
from x = 3 km to x = 4 km.
W = ................ kJ

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Oracle
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posted by PhysicsPhanatic on 2/17/2009 11:51:48 PM  |  status: Live
Asker's Rating: Lifesaver   
Response Details:
Work done = Area under curve = Force*distance
Part A:
W = (1/2)40*3
     = 60 kJ
Part B:
W = (1/2)40*1
     = 20 kJ
swb07c
Oracle
Karma Points: 75,603
posted by watt (MNK) on 2/18/2009 12:00:09 AM  |  status: Live
Asker's Rating: Helpful   
Response Details:
(A). work done  W = Area of the triangle
                              = ( 1/ 2) base * height
                              = 0.5 * 3 km * 40 N
                              = 0.5*3000 m * 40 N
                              = 60000 J
(B). work done = Area of the triangle = ( 1/ 2) * 1 km * 40 N
                                                         = 0.5 * 1000 m * 40 N
                                                         = 20000  J
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