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posted by  blink987 on 5/26/2009 10:34:11 PM  |  status: Closed  |  Earned Karma: 25

HELP, ASAP!!! prob 3, easy prob

Course Textbook Chapter Problem Needs by
Calculus Based Physics Physics for Scientists and Engineers 7th by Serway, Jewett 30 3P N/A
Question Details:
Please show me the work how to this prob thanks.
 

A wire with a current of 3.80 A is to be formed into a circular loop of one turn. If the required value of the magnetic field at the center of the loop is 10.0 µT, what is the required radius?

R = m
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posted by Harrison on 5/26/2009 10:44:49 PM  |  status: Live
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Response Details:
The magnetic field at the centre of the loop is given by,
B=μ0I/2R
10*10-6=4π*10-7*3.8/2R
Here R is the radius of the loop that.
Hence we get by it.
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posted by Priyo on 5/26/2009 11:03:00 PM  |  status: Live
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Response Details:
B=μ0 I /2r ∴r =μ0 I /2B

I= 3.8A
μ0 = 1.2566×10−6  T.m/A
B = 10.0 µT

∴r = 0.000000955016
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posted by zsm28 on 5/26/2009 11:14:04 PM  |  status: Live
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Response Details:
I = 3.80 A, B = 10.0 µT
B = μoI/(2R)
∴R = μoI/(2B) = 23.9 m
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