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posted by  steeler on 7/4/2009 2:25:53 AM  |  status: Live  |  Earned Karma: 25

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Course Textbook Chapter Problem Needs by
General Physics Physics (3rd) by Walker N/A N/A N/A
Question Details:
An archer shoots an arrow horizontally at a target 18 m away. The arrow is aimed directly at the center of the target, but it hits 56 cm lower. What was the initial speed of the arrow? (Neglect air resistance.)
1 m/s
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posted by steeler on 7/4/2009 2:43:38 AM  |  status: Live
Clarification Details:
i need the ANSWER  IM NOT GETTING IT

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posted by JamesD on 7/4/2009 2:34:55 AM  |  status: Live
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Response Details:
I hope this helps! Best of luck with the rest of your coursework.
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posted by D.J84 (MNK) on 7/4/2009 7:04:42 AM  |  status: Live
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Response Details:
56 cm=0.56 m

let initial horizontal velocity=u
horizontal acceleration=0

initial vertical velocity=0
vertical acceleration=g=9.8

time taken to hit the target=t

for vertical motion
s=u*t+(1/2)*g*t2
0.56=0+(1/2)*9.8*t2
t=0.34 s

for horizontal motion
18=u*t
18=u*0.34
u=52.94 m/s

initial speed of the arrow=52.94 m/s

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