homework help > physics > physics q&a board > topic: physics...

Q BgQuestion:

      
Pupil
Karma Points: 60
Respect (89%):
posted by  sean5 on 10/29/2009 9:21:34 PM  |  status: Live  |  Earned Karma: 60

physics

Course Textbook Chapter Problem Needs by
N/A N/A N/A N/A 10/29/2009 at 9:00:00 PM
Question Details:
a 5.7 kg bucket of water is raised from a well by a rope. the acceleration of gravity is 9.81 meters per second squared. if the upward acceleration of the bucket is 3.8 meters per second squared, find the force exerted by the rope on the bucket of water. answer in units of newtons.
Tags: Physics
Bonus Point Alert! Earn +8 additional karma points for helping this platinum member.

AAnswers:

Answer Question Ask for clarification
Oracle
Karma Points: 130,262
posted by Altair on 10/29/2009 9:27:19 PM  |  status: Live
Asker's Rating: Helpful   
Response Details:
let the force exerted by the rope on the bucket of water be F, we have:
F-mg = ma
=>F = ma+mg = m(a+g) = 5.7kg*(3.8m/s2 + 9.81m/s2) = 77.577 N
the force F is 77.577N

Don't forget give me good rating  to show your respect for my time to help you!
Oracle
Karma Points: 75,603
posted by watt (MNK) on 10/29/2009 9:30:18 PM  |  status: Live
Asker's Rating: Helpful   
Response Details:
mass m = 5.7 kg
accleration due to gravity  g = 9.81 m / s ^ 2
upward accleration  a = 3.8 m / s ^ 2
force exerted by the rope on the bucket  F = m ( a+ g )
                                                                 = 77.577 N
Answer Question Ask for clarificarion
Ask New Question

Join Cramster's Community

Cramster.com brings together students, educators and subject enthusiasts in an online study community. With around-the-clock expert help and a community of over 100,000 knowledgeable members, you can find the help you need, whenever you need it. Join for free today » How Cramster is different from tutoring »

Need Help In

Useful Links