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posted by  Dolores on 11/1/2009 10:00:54 PM  |  status: Closed  |  Earned Karma: 55

pendulum

Course Textbook Chapter Problem Needs by
General Physics College Physics (8th) by Serway, Faughn, Vuille N/A N/A 11/1/2009 at 11:00:00 PM
Question Details:
You are designing a pendulum clock escapement.  You have determined that the pendulum must have a period of .600s.  What should be the length of the thing?
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posted by Kevin_08 on 11/1/2009 10:05:49 PM  |  status: Live
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Response Details:
  The time period of the seconds pendulum is
            T = 2π√(L/g)
          
   The length of the pendulum is
                    L = (T2 g)/(4π2)

  Here T = 0.600 s
           g =9.80  m/s2

Substitute the values for L.
I hope this helps! Best of luck with the rest of your coursework.
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posted by Altair on 11/1/2009 10:06:00 PM  |  status: Live
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Response Details:
T = 2π √(L/g)  ,  here T is period, L is the length
=>L = g*(T/2π)2 = 9.8m/s2 *(0.600s/2*3.14)2 = 0.089 m
the length is 0.089m

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