(a)
   the moment of inertia of each system will be
   for the system A
   I = m₁ r₁² + m₂ r₂² + m₃ r₃² 
     = (8.40 kg) (0 m)² + (5.2 kg) (3.00 m)² + (5.00 kg) (5.00 m)²
     = ......... kg.m²
   for the system B
   I = m₁ r₁² + m₂ r₂² + m₃ r₃² 
     = (8.4 kg) (5.00 m)² + (5.2 kg) (4.00 m)² + (5.0 kg) (0 m)²
     = ......... kg.m²
(b)
   if same force of magnitude F = 446 N the torque will not be the saeme
   we know that
   τ = F l
   where l = 3.00 m
   in the system B the lever arm is l = 0, since the line of action of the force passes through the axis
   of rotation 
   for the system A the torque will be
   τ = - F l
      = - (446 N) (3.00 m)
      = ....... N.m
   for the system B the torque will be
   τ = F l
      = (446 N) (0 m)
      = 0 N.m

(c)
   the equation for the angular velocity is givenn by

   ω = ω_o + α t
   but α = (Σ τ / I)

   where Σ τ is the net torque and I is the moment of inertia
   in both the systems start from rest the initial angular velocity ω_o = 0 rad/s

   final angular velocity are after t = 10 s
   for system A

    ω = ω_o + (Σ τ / I) t
        = ........ rad/s

   for system B
    ω = ω_o + (Σ τ / I) t
        = ........ rad/s