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posted by  HoneyRamsey on 11/3/2009 2:59:22 PM  |  status: Closed  |  Earned Karma: 69

block attached to a spring

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General Physics N/A N/A N/A 11/3/2009 at 7:00:00 PM
Question Details:
A block attached to a spring with an unknown spring constant oscillates with a period of 4.0 s. What is the period if: a.    The mass is doubled?

b.    The mass is halved?

c.     The amplitude is doubled?

d.    The spring constant is doubled?
HoneyRamsey
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posted by JamesD on 11/3/2009 3:17:10 PM  |  status: Live
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Response Details:
 
the time period of the oscillation   T = 2π√(m/k)
(a) If the mass is doubled
   T α √m
so the time period becomes √2 times
 i.e.,  T = 4.0s * √2 = 5.65 s
(b) If the mass is havled
     T α √m
so the time period becomes 1/√2 times
 i.e.,  T = 4.0s * 1/√2 = 2.82s
(c) the amplitude is doubled
The time period is independent of amplitude
(d) The spring constant  is doubled
       T α 1/k
       so it becomes 1/√2 times
  i.e., T = 4.0s * 1/√2 = 2.82s
I hope this helps! Best of luck with the rest of your coursework.
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