we are given with
   mass of the block M = 2.50 kg
   displacement of the block s = 2.60 m
   force F = 16.0 N
   angle θ = 25^o
   acceleration due to gravity g = 9.80 m / s²  
   if M g is the weight of the block and R is the reaction force then
(a)
   the work done by the applied force will be
   W = F cosθ s
       = ...... J
(b)
   the work done by normal force exerted by the table will be   
   W = R s cos90^o
   but we can see that the force and the displacement are perpendicular to each other the work
   done will be zero
   W = 0 J
(c)
   work done by the force of gravity is
   W = M g s cos90^o
   but we can see that displacement and the weight of the block are perpendicular to each other the
   workdone will be zero
   so we get
   W = 0 J
(d)
   the work done by the net force on the block is W in part (a)