weight W = 35 N
angle θ = 30 degrees
The coefficient of kinetic friction between the block and the inclined plane is μ = 0.340
distance L = 2.01 m
(a). work done by gravity w= - W sin θ * L
= - 35.175 J
(b). Work done by applied force w ' = F * L
Since it moves with constant speed ,applied frce = frciotnal force + W sin θ
F = μW cos θ + W sin θ
= 27.8 N
So, w ' = 55.878 J
(c). work done by normal force w " = 0
Since normal force and displacement are perpendicular to each other