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posted by  dezzzzz on 11/4/2009 10:47:29 PM  |  status: Live  |  Earned Karma: 25

elastic collision

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N/A N/A N/A N/A 11/5/2009 at 11:00:00 AM
Question Details:
Hockey puck B rests on a smooth ice surface and is struck by a second puck A, which has the same mass. Puck A is initially traveling at 16.0 m/s and is deflected 28.0^\circ from its initial direction. Assume that the collision is perfectly elastic
Find the final speed of the puck B after the collision.
Find the final speed of the puck A after the collision.
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posted by jacksparrow on 11/4/2009 11:06:35 PM  |  status: Live
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Response Details:
Recall that momentum is always conserved. Since they are the same mass. There will be a symmetry when they collide. In other words they are both deflected from the original by the same angle, and they will have the same velocity.



Since this is perfectly elastic the energy before and after is the same.

Energy before = 0.5 m 162
Energy before = 128*m

Energy after  = 0.5 m v2 + 0.5 m v2
Energy after  = 2 * (0.5 m v2 )
Energy after  = m*v2


Energy before = Energy after
128 * m = m * v2
128 = v2
v = 11.31 m/s
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