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posted by  chancer on 11/5/2009 12:47:12 AM  |  status: Closed  |  Earned Karma: 50

AP Physics question

Course Textbook Chapter Problem Needs by
Algebra Based Physics N/A N/A N/A 11/5/2009 at 8:00:00 PM
Question Details:

A(n) 11.9 g bullet is shot into a(n) 6191 g

wooden block standing on a frictionless sur-

face. The block, with the bullet in it, acquires

a velocity of 1.47 m/s.

Calculate the velocity of the bullet before

striking the block.

Answer in units of m/s.
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posted by jerry2009 on 11/5/2009 12:56:07 AM  |  status: Live
Asker's Rating: Lifesaver   
Response Details:

    Mass of the bullet, m = 11.9 g = 0.0119 kg

    Mass of the block, M = 6191 g = 6.191 kg

    Velocity of the bullet + block after collision , V = 1.47 m/s

    Initial velocity of the bullet, U = ?

    From law of conservation of momentum,

    Momentum of the bullet before collision = Momentum of the bullet + block after collision

    m U = ( m + M ) V
 
    0.0119 * U = ( 0.0119 + 6.191 ) * 1.47

    Initial velocity of the bullet before collision, U = 766.24 m/s
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posted by Anonymous on 11/5/2009 1:06:44 AM  |  status: Live
Asker's Rating: Helpful   
Response Details:
Momentum conservation:

Plug in the numbers will give units of m/s
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