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posted by  sief25 on 11/5/2009 1:11:09 AM  |  status: Closed  |  Earned Karma: 25

angular accleration

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Algebra Based Physics N/A N/A N/A 11/5/2009 at 6:00:00 AM
Question Details:
  A 2.0 kg bike wheel, which can be taken as a hoop with a radius of 0.40 m and a 0.50 kg disk with a radius of 0.15 m are attached to a common axle and are initially rotating together at a constant angular velocity of 2.0 rev/s. A brake is applied to the outer edge of the disk such that the system comes to rest in 2.5s. (a) If it decelerates uniformly, what is the angular acceleration of the system during this 2.5 s? (b) What is the moment of inertia of the system? (c) What is the torque on the system? (d) How much frictional force is applied in order to stop the wheels? (Assume the axle and the bike tire spokes have negligible mass.)
 
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posted by watt (MNK) on 11/5/2009 1:40:35 AM  |  status: Live
Asker's Rating: Helpful   
Response Details:
Mass of wheel  m = 2 kg
radius of wheel  r = 0.4 m
Moment of inertia of wheel  I = m r ^ 2
                                            = 0.32 kg m ^ 2
mass of disk  m ' = 0.5 kg
radius of disk  r ' = 0.15 m
moment of inetia of disk I ' = ( 1/ 2) m ' r ' ^ 2
                                         = 0.005625 kg m ^ 2
(a). Initial angular speed  w = 2 rev / s= 2.5 * 2π rad / s
                                         = 15.707 rad / s
final angular speed w ' = 0
time t= 2.5 s
angular accleration α = ( w ' - w ) / t
                                = -6.283 rad / s ^ 2
(b). Moment of inertia of the system  I " = I + I '
                                                            = 0.325625 kg m ^ 2
(c). torque of the system  τ = I " α
                                         = 2.045 N m
(d). frictional force  F = τ / r
                                 = 5.114 N
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