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posted by  Mr.hero on 11/5/2009 2:20:59 AM  |  status: Closed  |  Earned Karma: 135

Easy Lifesaver Q

Course Textbook Chapter Problem Needs by
Calculus Based Physics Essential University Physics Volume 1 (1st) by Wolfson 28 55 11/8/2009 at 11:00:00 PM
Question Details:
A series RLC circuit has resistance 150 \Omega and impedance 300 \Omega.
Part A
What is the power factor?

Part B
f the rms current is 150 mA, what is the power dissipation?
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posted by Mobiusdick on 11/5/2009 2:42:14 AM  |  status: Live
Asker's Rating: Lifesaver   
Response Details:
a)PF = R/Z = 150/300 = 2.

b) P = Irms2R = .152*150 = 3.375W
(SME)
posted by esther_jyothi on 11/5/2009 2:46:07 AM  |  status: Live
Asker's Rating: Helpful   
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