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posted by  Chrissy0022 on 11/5/2009 2:34:05 AM  |  status: Live  |  Earned Karma: 404

local acceleration due to gravity on the moon

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General Physics N/A N/A N/A 11/5/2009 at 1:00:00 PM
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1.      To pass the time in the lunar space station waiting room you decide to measure the local acceleration due to gravity on the moon.  You do this by constructing a simple pendulum consisting of a 15 g steel ball suspended on a string that is 75cm long. If the pendulum completes 14 cycles in 1.0 min, what is the acceleration due to gravity (g) on the moon?

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posted by jerry2009 on 11/5/2009 3:17:15 AM  |  status: Live
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Response Details:


    Let

    Length of the pendulum, L = 0.75 m

    Mass of the pendulum , M = 15 g

    Time period, T = ( 1 / 14 ) min
                           = 60 / 14 s
                           = 4.29 s

    Time period, T = 2 π √ ( L / g )

    Acceleration due to gravity, g = 4 π2 ( L / T2 )

                                                  = 4 * π2 * ( 0.75 / 4.29 2 )

                                                  = 1.61 m/s2

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