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posted by  eddy143 on 11/5/2009 3:26:19 AM  |  status: Live  |  Earned Karma: 0

phy101 question 4 help plz

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N/A N/A N/A N/A 11/10/2009 at 6:00:00 PM
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Q 4

Two ice dancers are at rest on the ice, facing each other with their hands together. They push off on each other in order to set each other in motion. The subsequent momentum change (magnitude only) of the two skaters will be ____. Also write it’s (the answer you choose) detail reason.                                                                                              

 

A. greatest for the skater who is pushed upon with the greatest force

 

B. greatest for the skater who pushes with the greatest force

C. the same for each skater

D. greatest for the skater with the most mass

E. greatest for the skater with the least mass        

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posted by Physics-Ga on 11/5/2009 1:01:50 PM  |  status: Live
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C) The momentum of the system was zero before and after as there were no external
      forces acting on the system.
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posted by Tours2009 on 11/11/2009 12:28:28 AM  |  status: Live
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Answer: C

In this situation, the force on the first ice dancer is the same as the force on the second ice dancer (Newton's third law of motion). And these forces act for the same amount of time to cause equal impulses on each skater. Since impulse is equal to momentum change, both skaters must also have equal momentum changes. The mass of the individual skaters will only effect the subsequent velocity change.
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