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posted by  chupsmusica on 11/6/2009 12:41:41 PM  |  status: Live  |  Earned Karma: 25

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Course Textbook Chapter Problem Needs by
Calculus Based Physics Physics for Scientists and Engineers (6th) by Tipler, Mosca 8 85 11/6/2009 at 9:00:00 PM
Question Details:
In a pool game, the cue ball, which has an initial speed of 7.0 m/s, make an elastic collision with the eight ball, which is initially at rest. After the collision, the eight ball moves at an angle of 30° to the original direction of the cue ball.
(a) Find the direction of motion of the cue ball after the collision.
(b) Find the speed of each ball. Assume that the balls have equal mass.
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posted by Justin_08 on 11/6/2009 1:20:20 PM  |  status: Live
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posted by chupsmusica on 11/6/2009 5:05:17 PM  |  status: Live
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What are the steps I need to do to solve this problem?
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posted by Jimbojo on 11/6/2009 5:34:57 PM  |  status: Live
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This problem needs to be broken up into components of conservation of momentum.  Because there is no external force acting on your system, there is no change in the total momentum of the system.  This can be written for momentum in both directions as follows:




NOTE: IN EACH EQUATION, SECOND THETA IS A DISTINCT AND NEW ANGLE.

The minus sign in the ρy equation is because mass 1 is moving downward at that time, and we have chosen up and right as our positive coordinate axis.  Finding the direction of the ball can be done a multitude of ways (any way you can solve for θ).  But first, keep in mind m1=m2, so you can eliminate mass out of the problem.  The angle for the second ball is:

cos-1[]

Since it's an elastic collision, you also know that V1 + V1F = V2 + V2F

Knowing these equations and being able to solve, plug, and solve, you should be able to get it.  Good luck.
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