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posted by  cortneyp on 11/7/2009 1:14:21 AM  |  status: Closed  |  Earned Karma: 25

Refraction

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2. An expensive spotlight is located at the bottom of a gold-plated swimming pool of depth d = 2.70 m (see Figure). Determine the diameter of the circle from which light emerges from the tranquil surface of the pool.  m


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posted by E=mc*c (MNV) on 11/7/2009 4:27:00 AM  |  status: Live
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Response Details:
FOR WATER AIR INTERFACE THE ANGLE OF incidence
 =C
sin C = 1/μ = 1/1.33 = 0.7518
so C  = 48.75 degree.
now tan48.75=radius of the circle/2.7
so radius of the circle=2.7tan48.75=3.079
so diameter of the circle=6.158m
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