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posted by  frank801 on 11/7/2009 1:38:27 AM  |  status: Closed  |  Earned Karma: 115

Temperature and Heat 5

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N/A N/A N/A N/A 11/10/2009 at 11:00:00 PM
Question Details:
A cube of ice is taken from the freezer at -8oC and placed in a 80 g aluminum calorimeter filled with 260 g of water at a temperature of 24oC. The final situation is observed to be all water at 13oC. What was the mass of the ice cube?(cwater=4186 J/kg.oC, cal=900 J/kg.oC, cice=2000 J/kg.oC, Lf=33.5x104 J/kg)
frank
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Oracle
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posted by kwyjibo on 11/7/2009 2:36:54 AM  |  status: Live
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Response Details:
Qaluminum + Q water = Q ice
Qaluminum = mass aluminum*heat capacity*ΔT
Qwater= mass water*heat capacity*ΔT
Q ice = mass_ice*heat capacity of ice*ΔT1+  latent heat + mass_ice*heat capacity of water *ΔT2
ΔT1 = -8C to 0 C
ΔT2 = 0 C to 13 C

Qaluminum + Q water = Q ice
80g *(900 J/kg-C)*(24 C - 13 C) + 260 g *(4186 J/kg-C)*(24 C - 13 C)
= m*(2000 J/kg-C)*(0 C - [-8]C) + m*(33.5e4 J/kg) + m*(4186 J/kg-C)*(24C - 0 C)

12862960  g*J/kg =  450464*m   J/kg
m = 28.6 grams
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