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posted by  C' on 11/7/2009 3:00:33 AM  |  status: Closed  |  Earned Karma: 28

What is the magnitude of the magnetic force this charge experiences?

Course Textbook Chapter Problem Needs by
General Physics Physics for Scientists and Engineers 7th by Serway, Jewett 29 7 11/7/2009 at 11:00:00 PM
Question Details:
A proton moves with a velocity of vector v = (1ihatbold - 3jhatbold + khatbold) m/s in a region in which the magnetic field is vector B = (ihatbold + 2jhatbold - 3khatbold) T. What is the magnitude of the magnetic force this charge experiences?
Your answer was incorrect, but has changed from what was graded.
Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. N
I've redone my cross product twice to see if I made a small error but I just can't find it; it's driving me crazy ;p
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AAnswers:

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posted by esther_jyothi on 11/7/2009 3:14:32 AM  |  status: Live
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Response Details:
Sage
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posted by Mr. SinghSoorma on 11/7/2009 3:21:57 AM  |  status: Live
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Response Details:
F = qv X b
Qproton = (1.602 x 10 ^ - 19 C)
Fx = Vy Bz - Vz By = (-3*-3) - (1*2) = 9 - 2 = 7Q = 1.1214 E -18
Fy = VzBx - VxBz = ( 1 *1 ) - (1*-3) = 1 + 3 = 4Q = 6.408 E -19
Fz = VxBy - VyBx = (1*2) - (-3*1) = 2 + 3 = 5Q = 8.01 E -19

Fmag = 
Fmag = 1.5198 x 10^-18 N



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