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posted by  Sunnysideofthewall on 11/7/2009 8:54:25 AM  |  status: Closed  |  Earned Karma: 0

Chapter 8 Problem 52

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Calculus Based Physics Fundamentals of Physics Extended (8th) by Halliday, Resnick, Walker 8 52 11/11/2009 at 8:30:00 PM
Question Details:
You push a 2.2 kg block against a horizontal spring, compressing the spring by 26 cm. Then you release the block, and the spring sends it sliding across a tabletop. It stops 76 cm from where you released it. The spring constant is 400 N/m. What is the coefficient of kinetic friction between the block and the table?

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posted by Physics-Ga on 11/7/2009 3:28:15 PM  |  status: Live
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Response Details:
1/2 k x2 = μ m g * .76     all of the energy of the spring is dissipated by friction
μ = k x2 / (2 * .76 * m g)
μ = 400 * .262 / (1.52 * 2.2 * 9.8) = .825
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