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posted by  boboknight on 11/7/2009 9:46:41 AM  |  status: Closed  |  Earned Karma: 50

Spring

Course Textbook Chapter Problem Needs by
Calculus Based Physics Principles of Physics (3rd) by Serway, Jewett N/A N/A 11/12/2009 at 8:00:00 PM
Question Details:
A 0.500kg mass oscillates in simple harmonic motion at the end of a spring of constant 150N/m. The total energy of the system is 2.50J. What is the maximum speed of the mass (in m/s)?


Hint:

For a mass on a spring: E = (1/2) k (x(max))^2 = (1/2) m (v(max))^2
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posted by watt (MNK) on 11/7/2009 9:54:27 AM  |  status: Live
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Response Details:
Modified:
----------
mass m = 0.5 kg
Spring constant  k = 150 N / m
Total energy  E = 2.5 J
we know  E = ( 1/ 2) m v ^ 2
from this maximum speed of the mass   v = √[ 2E / m ]
                                                              = 3.1622m / s
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