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posted by  boboknight on 11/7/2009 9:49:13 AM  |  status: Closed  |  Earned Karma: 50

Spring

Course Textbook Chapter Problem Needs by
Calculus Based Physics Principles of Physics (3rd) by Serway, Jewett N/A N/A 11/12/2009 at 8:00:00 PM
Question Details:
A 0.500kg mass is attached to a spring of constant 150N/m. A driving force F(t) = ( 12.0N) cos(wt) is applied to the mass, and the damping coefficient b is 6.00Ns/m. What is the amplitude (in cm) of the steady-state motion if w is equal to half of the natural frequency w0 of the system?

Hint:

This is a forced oscillation problem.

A = (F0/m)/sqrt[(w^2-w0^2)^2+(bw/m)^2]

w0^2 = k/m = 300, w = w0/2, w^2 = 300/4 = 75.

F0/m = 12/0.5 = 24
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posted by zsm28 on 11/7/2009 11:33:29 AM  |  status: Live
Asker's Rating: Lifesaver   
Response Details:
The hint is right, answer: 9.68 cm
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