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posted by  NDFLBO on 11/7/2009 9:52:59 AM  |  status: Closed  |  Earned Karma: 50

Pendulum

Course Textbook Chapter Problem Needs by
Calculus Based Physics Principles of Physics (3rd) by Serway, Jewett N/A N/A 11/11/2009 at 8:00:00 PM
Question Details:
A simple pendulum has a period of 2.8s. What is its length (in m)?

Hint:
The period of a simple pendulum is given by T = 2*pi*sqrt(L/g).  Here the period is 2.8s, g = 9.8m/s^2, solve for L.
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posted by watt (MNK) on 11/7/2009 10:00:32 AM  |  status: Live
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Response Details:
Time period T = 2π √[ L / g]
from this length of the pendulum  L = g ( T / 2π) ^ 2
                                                     = 9.8 ( 2.8 / 2π) ^ 2
                                                     = 1.946 m
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