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posted by  Haste on 11/7/2009 10:17:32 AM  |  status: Live  |  Earned Karma: 546

Find the friction force impeding its motion.

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Question Details:
A 23.0 kg box is released on a 35.0° incline and accelerates down the incline at 0.272 m/s2. Find the friction force impeding its motion.

What is the coefficient of kinetic friction?
Tags: Physics
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posted by christina.S on 11/7/2009 10:28:06 AM  |  status: Live
Asker's Rating: Helpful   
Response Details:
(a)We know that  :
.
         Frictional force is :  Fr  =  m g   sinθ   =  ( 23.0 * 9.8 * cos35 )  =  184.63  N
.
(b) We have :
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                           m a  =  m g   sinθ   -  μ mg  cosθ
.
         or  μ mg  cosθ   =    mg  sinθ  -  ma
.
                     μ           =    (   mg  sinθ  -  ma  ) /  mg  cosθ  
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                                   =  ( 184.63    -  23.0 * 0.272  ) / (23.0 * 9.8 * cos35 )
.
                                   =     0.966 
.
Hope this helps u!
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