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posted by  rocky888 on 11/5/2009 2:24:20 AM  |  status: Closed  |  Earned Karma: 50

Exponential Distribution how to call calculate F(X)

Course Textbook Chapter Problem Needs by
Statistics and Probability A First Course in Probability (6th) by Ross 5 Example 5.b 11/5/2009 at 11:00:00 AM
Question Details:
Hi i was wondering if someone could explain the following as referred to in red, many thanks:

Example 5b. Suppose that the length of a phone call in minutes is an exponential random variable with parameter λ = 1/10. If someone arrives immediately ahead of you at a public telephone booth, find the probability that you will have to wait

(a) more than 10 minutes;
(b) between 10 and 20 minutes.

Solution: Letting X denote the length of the call made by the person in the booth, we have that the desired probabilities are:
(a) P { X > 10 } = 1 - F(10)
"where is this gotten from"
                         = e^-1 = .368 "how do we get to this line from the previous .i.e. how to work out F(10)"
(b) P { 10 < X < 20 } = F(20) - F(10)
                                  = e^-1 - e^-2 = .233






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Guru
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posted by Orca on 11/5/2009 2:40:07 AM  |  status: Live
Asker's Rating: Helpful   
Response Details:
F(x) is the cumulative distribution function.  that is
P(Xx)=F(x)
Since,   
f(x)=λe-λx,    x0
F(x)=
Note
P(X>10)=1-F(10)
P(10<X<20)=F(20)-F(10)
Novice
Karma Points: 42
posted by Anonymous on 11/5/2009 2:50:44 AM  |  status: Live
Asker's Rating: Helpful   
Response Details:
There is a formula in which exponential random variable is modelized to depict waiting time at telephone booths .
 f(x) = λe ^ (-λx) . This formula has been used in the question.
To obtain probability of waiting we have a formula :
 P(T>t ) = e^(-λt)  and P(a<=T<b)=e^(-λa)-e^(-λb)
In the question λ=1/10 and t=10 , a=10 , b=20 . Substituting the value the answer has been obtained.
Sak
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