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posted by  cool mona on 11/7/2009 6:15:21 AM  |  status: Closed  |  Earned Karma: 1112

poisson probability problem. pls help

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1.           Serious worker injuries at a steel-fabricating company average 2.1 per year.

(a) Given that the safety conditions at the plant remain the same next year, what is the probability that the number of serious injuries will be less than 2?

(b) How many serious injuries would you expect next year?

(c) What is the variance for the numbers of serious injuries next year?

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posted by Jonpp on 11/7/2009 12:22:13 PM  |  status: Live
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Response Details:
X~Poisson(λ=2.1)

(a)P(X<2)=P(X=0)+P(X=1)=0.3796

(b)λ=2.1

(c)λ=2.1
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